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6v^2-8=424
We move all terms to the left:
6v^2-8-(424)=0
We add all the numbers together, and all the variables
6v^2-432=0
a = 6; b = 0; c = -432;
Δ = b2-4ac
Δ = 02-4·6·(-432)
Δ = 10368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10368}=\sqrt{5184*2}=\sqrt{5184}*\sqrt{2}=72\sqrt{2}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72\sqrt{2}}{2*6}=\frac{0-72\sqrt{2}}{12} =-\frac{72\sqrt{2}}{12} =-6\sqrt{2} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72\sqrt{2}}{2*6}=\frac{0+72\sqrt{2}}{12} =\frac{72\sqrt{2}}{12} =6\sqrt{2} $
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